Deceit & Misrepresentation Leuchter, Rudolf and the Iron Blues v. 6.0 N Appendix II
Carbon dioxide (CO2) is an acid anhydride, which means that
when it is dissolved in water it lowers the pH of the solution. In fact
pure rainwater has a pH of 5.6 because of the 360 ppm atmospheric
concentration of CO2. During World War II, atmospheric
concentrations of CO2 were closer to 330 ppm, but that is not
an important difference for the purposes addressed here. One
can think of the process as having three steps all of which involve a
chemical equilibrium. The first step, is the dissolution of
CO2 in water and its equilibrium constant is the Henry's
Law constant of CO2, Khc:
The second step is the acid base reaction between carbonic acid and
water; its equilibrium constant is denoted here as Kc1:
H2CO3 + H2O <=>
H3O+ + HCO3-
Also, one needs to consider the autoprotolysis of water:
In aqueous solution, one can treat the concentration of water as a
constant and derive a constant for the equilibrium, Kw.
These constants and their associated enthalpies are reported in
Seinfeld1. Here is a table of the
relevant quantities:
The slight temperature dependence of these constants can be accounted
for by means of the enthalpies given. The pH of a solution is defined
as -log[H+] where [H+] is the concentration of
hyronium ions in moles/liter. From the information given it is possible
to derive a cubic equation expressing the relationship between
[H+] and the partial pressure of CO2,
PCO2. This equation is also presented in
Seinfeld:1
The Techniques of Holocaust Denial
Writer: Richard Green
The Effect of Carbon Dioxide on pH
CO2 + H2O <=> H2CO3
The third step is reaction between the bicarbonate ion
(HCO3-) and water whose equilibrium constant is here
denoted as Kc2:
HCO3- + H2O <=>
H3O+ + CO32-
2H2O <=> H3O+ + OH-
Table II.1: Equilibrium Constants and Associated
Enthalpies for the Absorption of Carbon Dioxide by Water.
Constant Value Enthalpy at 298 K
kcal/mole
Khc 3.4 x 10-2 -4.846
Kc1 4.283 x 10-7 1.825
Kc2 4.687 x 10-11 3.55
Kw 1.008 x 10-14 13.345
[H+]3 - (Kw+KhcKc1
PCO2)[H+]-2+KhcKc1
Kc2PCO2=0
I solved this equation by means of a simple computer program employing a
rootfinding method similar to Newton's method.2 The results are shown in figure
II.1.
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